Posted in PHP onJuly 25, 2014
获取到一个短连接,需要将短连接转换成真实的网址,通过查资料,发现 PHP 提供了一个函数 get_headers() ,可以完成这个任务,先把 头部信息获取到,然后再分析跳转地址即可:
$url = 'http://t.cn/h5mwx'; $headers = get_headers($url, TRUE); print_r($headers); //输出跳转到的网址 echo $headers['Location'];
附完整数组:
Array ( [0] => HTTP/1.1 302 Moved Temporarily [Location] => http://www.baidu.com [Content-Type] => Array ( [0] => text/html;charset=UTF-8 [1] => text/html;charset=utf-8 ) [Server] => Array ( [0] => weibo [1] => BWS/1.0 ) [Content-Length] => Array ( [0] => 203 [1] => 16424 ) [Date] => Array ( [0] => Thu, 12 Dec 2013 10:42:25 GMT [1] => Thu, 12 Dec 2013 10:42:25 GMT ) [X-Varnish] => 2893360335 [Age] => 0 [Via] => 1.1 varnish [Connection] => Array ( [0] => close [1] => Close ) )
附:get_headers函数官方文档
get_headers — 取得服务器响应一个 HTTP 请求所发送的所有标头
说明
array get_headers ( string $url [, int $format = 0 ] )
get_headers() 返回一个数组,包含有服务器响应一个 HTTP 请求所发送的标头。
参数
url:目标 URL。
format:如果将可选的 format 参数设为 1,则 get_headers() 会解析相应的信息并设定数组的键名。
返回值
返回包含有服务器响应一个 HTTP 请求所发送标头的索引或关联数组,如果失败则返回 FALSE。
使用例子:
<?php $url = 'http://www.example.com'; print_r(get_headers($url)); print_r(get_headers($url, 1)); ?>
以上例程的输出类似于:
Array ( [0] => HTTP/1.1 200 OK [1] => Date: Sat, 29 May 2004 12:28:13 GMT [2] => Server: Apache/1.3.27 (Unix) (Red-Hat/Linux) [3] => Last-Modified: Wed, 08 Jan 2003 23:11:55 GMT [4] => ETag: "3f80f-1b6-3e1cb03b" [5] => Accept-Ranges: bytes [6] => Content-Length: 438 [7] => Connection: close [8] => Content-Type: text/html ) Array ( [0] => HTTP/1.1 200 OK [Date] => Sat, 29 May 2004 12:28:14 GMT [Server] => Apache/1.3.27 (Unix) (Red-Hat/Linux) [Last-Modified] => Wed, 08 Jan 2003 23:11:55 GMT [ETag] => "3f80f-1b6-3e1cb03b" [Accept-Ranges] => bytes [Content-Length] => 438 [Connection] => close [Content-Type] => text/html )
PHP获取短链接跳转后的真实地址和响应头信息的方法
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junjie声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
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