Posted in Python onDecember 11, 2020
import cv2 import numpy as np import matplotlib.pyplot as plt # Grayscale def BGR2GRAY(img): # Grayscale gray = 0.2126 * img[..., 2] + 0.7152 * img[..., 1] + 0.0722 * img[..., 0] return gray # Bi-Linear interpolation def bl_interpolate(img, ax=1., ay=1.): if len(img.shape) > 2: H, W, C = img.shape else: H, W = img.shape C = 1 aH = int(ay * H) aW = int(ax * W) # get position of resized image y = np.arange(aH).repeat(aW).reshape(aW, -1) x = np.tile(np.arange(aW), (aH, 1)) # get position of original position y = (y / ay) x = (x / ax) ix = np.floor(x).astype(np.int) iy = np.floor(y).astype(np.int) ix = np.minimum(ix, W-2) iy = np.minimum(iy, H-2) # get distance dx = x - ix dy = y - iy if C > 1: dx = np.repeat(np.expand_dims(dx, axis=-1), C, axis=-1) dy = np.repeat(np.expand_dims(dy, axis=-1), C, axis=-1) # interpolation out = (1-dx) * (1-dy) * img[iy, ix] + dx * (1 - dy) * img[iy, ix+1] + (1 - dx) * dy * img[iy+1, ix] + dx * dy * img[iy+1, ix+1] out = np.clip(out, 0, 255) out = out.astype(np.uint8) return out # make image pyramid def make_pyramid(gray): # first element pyramid = [gray] # each scale for i in range(1, 6): # define scale a = 2. ** i # down scale p = bl_interpolate(gray, ax=1./a, ay=1. / a) # add pyramid list pyramid.append(p) return pyramid # Read image img = cv2.imread("../bird.png").astype(np.float) gray = BGR2GRAY(img) # pyramid pyramid = make_pyramid(gray) for i in range(6): cv2.imwrite("out_{}.jpg".format(2**i), pyramid[i].astype(np.uint8)) plt.subplot(2, 3, i+1) plt.title('1/' + str((i+1)**2) ) plt.imshow(pyramid[i], cmap='gray') plt.axis('off') plt.xticks(color="None") plt.yticks(color="None") plt.show()
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python实现图像高斯金字塔的示例代码
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