Posted in Python onAugust 20, 2018
本文实例讲述了Python模拟简单电梯调度算法。分享给大家供大家参考,具体如下:
经常在公司坐电梯,由于楼层较高,是双联装的电梯,但是经常等电梯很久,经常有人骂写电梯调度算法的。回来闲来无事,自己尝试写了一个简单的。
场景很简单,每一层电梯口只有一个按钮,不区分上下,当有人按下这个键后,电梯会过来停在此层,这个人可以进去,并选择自己想去的层。电梯的调度策略也很简单,在一次向上的过程中,如果有人在下面按了键,电梯并不直接向下,而是运行到此次向上的最顶层,然后再下次向下运行的过程中去服务这个请求。
elevator.py
import time from myque import myque class elevator: def __init__(self,layers): self.building_layers = layers self.direction = 'up' self.cur_layer = 1 self.up_queue = myque() self.down_queue = myque(True) self.switcher = 'open' def stop(self): self.switcher='stop' def push_button(self,layer,direction=None): if self.cur_layer>layer: self.down_queue.insert(layer) elif self.cur_layer<layer: self.up_queue.insert(layer) else: if self.direction=='up': self.down_queue.insert(layer) else: self.up_queue.insert(layer) def handle_queue(self,direction): self.direction = direction if direction == 'up': inc = 1 else: inc = -1 que = getattr(self , direction + '_queue') while que.length(): while self.cur_layer != que.front(): print '/nelevator in ',self.cur_layer time.sleep(1) self.cur_layer += inc print '/nelevator arrives at ',self.cur_layer que.pop_front() def run(self): while self.switcher=='open': if self.up_queue.empty() and self.down_queue.empty(): """elevator now is waiting, stop at a layer""" time.sleep(1) continue """go up""" self.handle_queue('up') """go down""" self.handle_queue('down')
myque.py
import threading class myque: def __init__(self,reverse=False): self.mode = reverse self.buf = [] self.lock = threading.Lock() def insert(self,object): self.lock.acquire() self.buf.append(object) self.buf.sort(reverse = self.mode) self.lock.release() def front(self): return self.buf[0] def pop_front(self): self.lock.acquire() self.buf.pop(0) self.lock.release() def length(self): self.lock.acquire() size = len(self.buf) self.lock.release() return size def empty(self): self.lock.acquire() size = len(self.buf) self.lock.release() return size==0
deploy.py
import threading from elevator import elevator def init_elevator(building_layers): e = elevator(building_layers) t = threading.Thread(target = e.run) t.setDaemon(True) t.start() return (e,t) def main(): myelevator,ctl_thread = init_elevator(17) while True: str=raw_input("Input valid layer :") try: layer = int(str) except Exception: if str=='quit': myelevator.stop() ctl_thread.join() break else: print 'invalid input',str continue if layer not in range(1,myelevator.building_layers+1): continue myelevator.push_button(layer) if __name__=='__main__': main()
运行结果如下:
如果扩展的话,很容易将各层的按钮扩展为带上下指示的。如果有机会可以扩展为多联装电梯,并将调度算法做的更加智能,可以根据历史数据和时间进行动态调整。
希望本文所述对大家Python程序设计有所帮助。
Python模拟简单电梯调度算法示例
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