Posted in Python onJanuary 08, 2018
本文实例为大家分享了微信小程序跳一跳自动运行脚本,供大家参考,具体内容如下
1、压缩包带了adb等必须工具,配置一下环境变量即可
2、Python 直接运行即可 (Python3.6)
代码:
wechat_jump_auto.py
# coding: utf-8 ''' # === 思路 === # 核心:每次落稳之后截图,根据截图算出棋子的坐标和下一个块顶面的中点坐标, # 根据两个点的距离乘以一个时间系数获得长按的时间 # 识别棋子:靠棋子的颜色来识别位置,通过截图发现最下面一行大概是一条直线,就从上往下一行一行遍历, # 比较颜色(颜色用了一个区间来比较)找到最下面的那一行的所有点,然后求个中点, # 求好之后再让 Y 轴坐标减小棋子底盘的一半高度从而得到中心点的坐标 # 识别棋盘:靠底色和方块的色差来做,从分数之下的位置开始,一行一行扫描,由于圆形的块最顶上是一条线, # 方形的上面大概是一个点,所以就用类似识别棋子的做法多识别了几个点求中点, # 这时候得到了块中点的 X 轴坐标,这时候假设现在棋子在当前块的中心, # 根据一个通过截图获取的固定的角度来推出中点的 Y 坐标 # 最后:根据两点的坐标算距离乘以系数来获取长按时间(似乎可以直接用 X 轴距离) ''' import os import sys import subprocess import time import math from PIL import Image import random from six.moves import input import debug, config import numpy as np VERSION = "1.1.1" debug_switch = False # debug 开关,需要调试的时候请改为:True config = config.open_accordant_config() # Magic Number,不设置可能无法正常执行,请根据具体截图从上到下按需设置,设置保存在 config 文件夹中 under_game_score_y = config['under_game_score_y'] press_coefficient = config['press_coefficient'] # 长按的时间系数,请自己根据实际情况调节 piece_base_height_1_2 = config['piece_base_height_1_2'] # 二分之一的棋子底座高度,可能要调节 piece_body_width = config['piece_body_width'] # 棋子的宽度,比截图中量到的稍微大一点比较安全,可能要调节 screenshot_way = 2 def pull_screenshot(): ''' 新的方法请根据效率及适用性由高到低排序 ''' global screenshot_way if screenshot_way == 2 or screenshot_way == 1: process = subprocess.Popen('adb shell screencap -p', shell=True, stdout=subprocess.PIPE) screenshot = process.stdout.read() if screenshot_way == 2: binary_screenshot = screenshot.replace(b'\r\n', b'\n') else: binary_screenshot = screenshot.replace(b'\r\r\n', b'\n') f = open('autojump.png', 'wb') f.write(binary_screenshot) f.close() elif screenshot_way == 0: os.system('adb shell screencap -p /sdcard/autojump.png') os.system('adb pull /sdcard/autojump.png .') def set_button_position(im): ''' 将 swipe 设置为 `再来一局` 按钮的位置 ''' global swipe_x1, swipe_y1, swipe_x2, swipe_y2 w, h = im.size left = int(w / 2) top = int(1584 * (h / 1920.0)) left = int(random.uniform(left-50, left+50)) top = int(random.uniform(top-10, top+10)) # 随机防 ban swipe_x1, swipe_y1, swipe_x2, swipe_y2 = left, top, left, top def jump(distance): ''' 跳跃一定的距离 ''' press_time = distance * press_coefficient press_time = max(press_time, 200) # 设置 200ms 是最小的按压时间 press_time = int(press_time) cmd = 'adb shell input swipe {x1} {y1} {x2} {y2} {duration}'.format( x1=swipe_x1, y1=swipe_y1, x2=swipe_x2, y2=swipe_y2, duration=press_time ) print(cmd) os.system(cmd) return press_time def find_piece_and_board(im): ''' 寻找关键坐标 ''' w, h = im.size piece_x_sum = 0 piece_x_c = 0 piece_y_max = 0 board_x = 0 board_y = 0 scan_x_border = int(w / 8) # 扫描棋子时的左右边界 scan_start_y = 0 # 扫描的起始 y 坐标 im_pixel = im.load() # 以 50px 步长,尝试探测 scan_start_y for i in range(int(h / 3), int(h*2 / 3), 50): last_pixel = im_pixel[0, i] for j in range(1, w): pixel = im_pixel[j, i] # 不是纯色的线,则记录 scan_start_y 的值,准备跳出循环 if pixel[0] != last_pixel[0] or pixel[1] != last_pixel[1] or pixel[2] != last_pixel[2]: scan_start_y = i - 50 break if scan_start_y: break print('scan_start_y: {}'.format(scan_start_y)) # 从 scan_start_y 开始往下扫描,棋子应位于屏幕上半部分,这里暂定不超过 2/3 for i in range(scan_start_y, int(h * 2 / 3)): for j in range(scan_x_border, w - scan_x_border): # 横坐标方面也减少了一部分扫描开销 pixel = im_pixel[j, i] # 根据棋子的最低行的颜色判断,找最后一行那些点的平均值,这个颜色这样应该 OK,暂时不提出来 if (50 < pixel[0] < 60) and (53 < pixel[1] < 63) and (95 < pixel[2] < 110): piece_x_sum += j piece_x_c += 1 piece_y_max = max(i, piece_y_max) if not all((piece_x_sum, piece_x_c)): return 0, 0, 0, 0 piece_x = int(piece_x_sum / piece_x_c) piece_y = piece_y_max - piece_base_height_1_2 # 上移棋子底盘高度的一半 # 限制棋盘扫描的横坐标,避免音符 bug if piece_x < w/2: board_x_start = piece_x board_x_end = w else: board_x_start = 0 board_x_end = piece_x for i in range(int(h / 3), int(h * 2 / 3)): last_pixel = im_pixel[0, i] if board_x or board_y: break board_x_sum = 0 board_x_c = 0 for j in range(int(board_x_start), int(board_x_end)): pixel = im_pixel[j, i] # 修掉脑袋比下一个小格子还高的情况的 bug if abs(j - piece_x) < piece_body_width: continue # 修掉圆顶的时候一条线导致的小 bug,这个颜色判断应该 OK,暂时不提出来 if abs(pixel[0] - last_pixel[0]) + abs(pixel[1] - last_pixel[1]) + abs(pixel[2] - last_pixel[2]) > 10: board_x_sum += j board_x_c += 1 if board_x_sum: board_x = board_x_sum / board_x_c last_pixel = im_pixel[board_x, i] # 从上顶点往下 +274 的位置开始向上找颜色与上顶点一样的点,为下顶点 # 该方法对所有纯色平面和部分非纯色平面有效,对高尔夫草坪面、木纹桌面、药瓶和非菱形的碟机(好像是)会判断错误 for k in range(i+274, i, -1): # 274 取开局时最大的方块的上下顶点距离 pixel = im_pixel[board_x, k] if abs(pixel[0] - last_pixel[0]) + abs(pixel[1] - last_pixel[1]) + abs(pixel[2] - last_pixel[2]) < 10: break board_y = int((i+k) / 2) # 如果上一跳命中中间,则下个目标中心会出现 r245 g245 b245 的点,利用这个属性弥补上一段代码可能存在的判断错误 # 若上一跳由于某种原因没有跳到正中间,而下一跳恰好有无法正确识别花纹,则有可能游戏失败,由于花纹面积通常比较大,失败概率较低 for l in range(i, i+200): pixel = im_pixel[board_x, l] if abs(pixel[0] - 245) + abs(pixel[1] - 245) + abs(pixel[2] - 245) == 0: board_y = l+10 break if not all((board_x, board_y)): return 0, 0, 0, 0 return piece_x, piece_y, board_x, board_y def check_screenshot(): ''' 检查获取截图的方式 ''' global screenshot_way if os.path.isfile('autojump.png'): os.remove('autojump.png') if (screenshot_way < 0): print('暂不支持当前设备') sys.exit() pull_screenshot() try: Image.open('./autojump.png').load() print('采用方式 {} 获取截图'.format(screenshot_way)) except Exception: screenshot_way -= 1 check_screenshot() def yes_or_no(prompt, true_value='y', false_value='n', default=True): default_value = true_value if default else false_value prompt = '%s %s/%s [%s]: ' % (prompt, true_value, false_value, default_value) i = input(prompt) if not i: return default while True: if i == true_value: return True elif i == false_value: return False prompt = 'Please input %s or %s: ' % (true_value, false_value) i = input(prompt) def main(): ''' 主函数 ''' op = yes_or_no('请确保手机打开了 ADB 并连接了电脑,然后打开跳一跳并【开始游戏】后再用本程序,确定开始?') if not op: print('bye') return print('程序版本号:{}'.format(VERSION)) debug.dump_device_info() check_screenshot() i, next_rest, next_rest_time = 0, random.randrange(3, 10), random.randrange(5, 10) while True: pull_screenshot() im = Image.open('./autojump.png') # 获取棋子和 board 的位置 piece_x, piece_y, board_x, board_y = find_piece_and_board(im) ts = int(time.time()) print(ts, piece_x, piece_y, board_x, board_y) set_button_position(im) jump(math.sqrt((board_x - piece_x) ** 2 + (board_y - piece_y) ** 2)) if debug_switch: debug.save_debug_screenshot(ts, im, piece_x, piece_y, board_x, board_y) debug.backup_screenshot(ts) i += 1 if i == next_rest: print('已经连续打了 {} 下,休息 {}s'.format(i, next_rest_time)) for j in range(next_rest_time): sys.stdout.write('\r程序将在 {}s 后继续'.format(next_rest_time - j)) sys.stdout.flush() time.sleep(2) print('\n继续') i, next_rest, next_rest_time = 0, random.randrange(30, 100), random.randrange(10, 60) time.sleep(np.random.uniform(0.6,0.9)) # 为了保证截图的时候应落稳了,多延迟一会儿,随机值防 ban if __name__ == '__main__': main()
simple.py
# -*- coding: utf-8 -*- import numpy as np import cv2 import os import time import re # 屏幕截图 def pull_screenshot(path): os.system('adb shell screencap -p /sdcard/%s' % path) os.system('adb pull /sdcard/%s .' % path) # 根据x距离跳跃 def jump(distance, alpha): press_time = max(int(distance * alpha), 200) cmd = 'adb shell input swipe {} {} {} {} {}'.format(bx1, by1, bx2, by2, press_time) os.system(cmd) screenshot = 'screenshot.png' alpha = 0 bx1, by1, bx2, by2 = 0, 0, 0, 0 chess_x = 0 target_x = 0 fix = 1.6667 # 检查分辨率是否是960x540 size_str = os.popen('adb shell wm size').read() if size_str: m = re.search(r'(\d+)x(\d+)', size_str) if m: hxw = "{height}x{width}".format(height=m.group(2), width=m.group(1)) if hxw == "960x540": fix = 3.16 while True: pull_screenshot(screenshot) image_np = cv2.imread(screenshot) image_np = cv2.cvtColor(image_np, cv2.COLOR_BGR2RGB) gray = cv2.Canny(image_np, 20, 80) HEIGHT = image_np.shape[0] WIDTH = image_np.shape[1] bx1 = WIDTH / 2 bx2 = WIDTH / 2 by1 = HEIGHT * 0.785 by2 = HEIGHT * 0.785 alpha = WIDTH * fix # 获取棋子x坐标 linemax = [] for i in range(int(HEIGHT * 0.4), int(HEIGHT * 0.6)): line = [] for j in range(int(WIDTH * 0.15), int(WIDTH * 0.85)): if image_np[i, j, 0] > 40 and image_np[i, j, 0] < 70 and image_np[i, j, 1] > 40 and image_np[i, j, 1] < 70 and image_np[i, j, 2] > 60 and image_np[i, j, 2] < 110: gray[i, j] = 255 if len(line) > 0 and j - line[-1] > 1: break else: line.append(j) if len(line) > 5 and len(line) > len(linemax): linemax = line if len(linemax) > 20 and len(line) == 0: break chess_x = int(np.mean(linemax)) # 获取目标x坐标 for i in range(int(HEIGHT * 0.3), int(HEIGHT * 0.5)): flag = False for j in range(WIDTH): # 超过朋友时棋子上方的图案 if np.abs(j - chess_x) < len(linemax): continue if not gray[i, j] == 0: target_x = j flag = True break if flag: break # 修改检测图 gray[:, chess_x] = 255 gray[:, target_x] = 255 # 保存检测图 cv2.imwrite('detection.png', gray) print(chess_x, target_x) jump(float(np.abs(chess_x - target_x)) / WIDTH, alpha) # 等棋子落稳 time.sleep(np.random.random() + 1)
下载:微信小程序跳一跳自动运行脚本
更多内容大家可以参考专题《微信跳一跳》进行学习。
更多关于python安装教程的文章请参考《python各版本安装教程》
更多精彩书单,请点击python编程必备书单
领取干货:零基础入门学习python视频教程
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持三水点靠木。
微信跳一跳自动运行python脚本
- Author -
qq71413声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
Reply on: @reply_date@
@reply_contents@