Posted in Javascript onDecember 21, 2016
解决拦截器对ajax请求的的拦截
拦截器配置:
public boolean preHandle(HttpServletRequest request, HttpServletResponse response,Object obj) throws Exception { //获取判定登陆的session是否存在 String token = (String) request.getSession().getAttribute("token"); String postId = (String) request.getSession().getAttribute("postId"); if(token == null || token == ""){ String XRequested =request.getHeader("X-Requested-With"); if("XMLHttpRequest".equals(XRequested)){ response.getWriter().write("IsAjax"); }else{ response.sendRedirect("/m-web/user/toLogin"); } return false; } if(postId == null || postId == ""){ String XRequested =request.getHeader("X-Requested-With"); if("XMLHttpRequest".equals(XRequested)){ response.getWriter().write("IsAjax"); }else{ response.sendRedirect("/m-web/user/toLogin"); } return false; } return true; }
1、判断 String XRequested =request.getHeader("X-Requested-With") 的值,目的是判断是否是ajax请求。
2、response.getWriter().write("IsAjax");写出一个响应的数据给ajax,这样就可以在ajax里面做判断
判断的方式存在两种方式:
1)直接在ajax里面做判断(不建议)
success:function(data){ if(data == "IsAjax"){ window.location.href="m-web/user/toLogin" return; } }
2)改ajax源码然后在做压缩,是针对全局的方式来修改的(建议)
if ( isSuccess ) {// if no content if ( status === 204 || s.type === "HEAD" ) { statusText = "nocontent"; // if not modified } else if ( status === 304 ) { statusText = "notmodified"; // If we have data, let's convert it } else { statusText = response.state; success = response.data; error = response.error; isSuccess = !error; //解决ajax拦截问题 var result = responses.text; if(result.indexOf("IsAjax")>=0){ window.location.href="m-web/user/toLogin"; return; } } }
感谢阅读,希望能帮助到大家,谢谢大家对本站的支持!
解决拦截器对ajax请求的拦截实例详解
- Author -
lqh声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
Reply on: @reply_date@
@reply_contents@