Posted in PHP onOctober 10, 2019
之前做项目用到了事务回滚这个机制。我把代码贴出来多多交流给点意见,我用的是laravel 5.1bane版本的,
public static function createDeal($to_status, $params, $new_balance, $update = true) { \DB::beginTransaction(); try { $update_order_status = \DB::table('wallet_order') ->where('order_id', $params['order_id']) ->update(['to_status' => $to_status, 'update_time' => $params['pay_time']]); if (!$update_order_status) { throw new \Exception("update order error"); } $create_deal_status = \DB::table('wallet_deal') ->insert($params); if (!$create_deal_status) { throw new \Exception("create deal error"); } if ($update) { $update_manage_status = self::updateManage(['balance' => $new_balance, 'update_time' => $params['pay_time']], $params['from_user']); if (!$update_manage_status) { throw new \Exception("update manage error"); } } else { $manage_params = [ 'user_id' => intval($params['from_user']), 'balance' => $new_balance, 'add_time' => $params['pay_time'], 'update_time' => $params['pay_time'], ]; $create_manage_status = self::createManage($manage_params); if (!$create_manage_status) { throw new \Exception("create manage error"); } } \DB::commit(); } catch (\Exception $e) {
//异常处理进行回滚,自己想对应的业务 \DB::rollback(); $trouble_params = [ 'order_id' => $params['order_id'], 'deal_id' => $params['deal_id'], 'from_user' => $params['from_user'], 'to_user' => $params['to_user'], 'total_amount' => $params['total_amount'], 'add_time' => $params['pay_time'], 'type' => $params['type'], 'to_status' => $to_status ]; \DB::connection('mongodb') ->table('wallet_trouble') ->insert($trouble_params); } finally { self::createLog($params, $to_status); } }
以上这篇在laravel中实现事务回滚的方法就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持三水点靠木。
在laravel中实现事务回滚的方法
- Author -
chen529834149声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
Reply on: @reply_date@
@reply_contents@