Posted in Javascript onMay 05, 2016
本文实例讲述了使用jquery.form.js实现图片上传的方法。分享给大家供大家参考,具体如下:
testupfile2.php
<?php header('Content-type:text/html;charset=utf-8'); include_once 'includes/common.inc.php'; if(!empty($_FILES['upfile'])){ //文件格式 $image=array('image/jpg', 'image/jpeg', 'image/png', 'image/pjpeg', 'image/gif', 'image/bmp', 'image/x-png' ); $updir=$_SERVER['DOCUMENT_ROOT'].$_config['g']['baseUrl'].'/attached/images/'; $upfile=$_FILES['upfile']; $name=$upfile['name']; $ext=substr($upfile['name'],strpos($upfile['name'],'.')); $upname=md5(time().rand(1, 1000)).$ext; $type=$upfile['type']; $size=$upfile['size']; $tmp_name=$upfile['tmp_name']; $error=$upfile['error']; $ok=0; foreach ($image as $key=>$value) { if($type==$value)$ok=1; } if($ok=='1' && $error=='0'){ move_uploaded_file($tmp_name,$updir.$upname); //echo '<br>'.$tmp_name.'<br>'.$upname.'<br>'.$updir.'<br>'.$ext.'上传成功'; //echo '上传成功'; echo $upname; //$im=$updir.$upname; //echo $im; //echo '<img src='.$updir.$upname.' />'; //$views->assign('image',$upname); //$views->display('default/testupfile.html'); } else echo '上传失败2'; } else echo '上传失败1'; ?>
testupfile.html
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Insert title here</title> <script type="text/javascript" src="<!--{$baseUrl}-->/scripts/jquery.js"></script> <script type="text/javascript" src="<!--{$baseUrl}-->/scripts/jquery.form.js"></script> <script type="text/javascript"> $(function(){ //jquery.form image1 $("#upimage").bind("click",function(){ if($("#upfile").val()==""){ alert("请选择一个图片文件,再点击"); return; } $("#form1").ajaxSubmit({ url:"testupfile2.php", type:"POST", //date:"upfile=upfile", success:function(response){ alert(response); $("#ln").empty(); $("#ln").append("<img src='<!--{$baseUrl}-->/attached/images/"+response+"' width='100' height='60'/>"); $("#im1").val(response); }, error:function(msg){ alert("出错了"); } }); }); //jquery.form image2 $("#upimage2").bind("click",function(){ if($("#upfile2").val()==""){ alert("请选择一个图片文件,再点击2"); return; } $("#form2").ajaxSubmit({ url:"testupfile2.php", type:"POST", //date:"upfile=upfile2", success:function(response2){ alert(response2); $("#ln2").empty(); $("#ln2").append("<img src='<!--{$baseUrl}-->/attached/images/"+response2+"' width='100' height='60'/>"); $("#im2").val(response2); }, error:function(msg){ alert("出错了"); } }); }); }); </script> </head> <body> 文件上传 <form enctype="multipart/form-data" id="form1" method="post" action=""> 文件: <input type="file" name="upfile" id="upfile"><input type="button" id="upimage" value="图片上传1"> <input type="text" name="im1" id="im1" value="" /> </form> <form enctype="multipart/form-data" id="form2" method="post" action=""> 文件: <input type="file" name="upfile" id="upfile2"><input type="button" id="upimage2" value="图片上传2"> <input type="text" name="im2" id="im2" value="" /> </form> <div id="ln">tu</div><br> <div id="ln2">tu2</div> </body> </html>
希望本文所述对大家jQuery程序设计有所帮助。
使用jquery.form.js实现图片上传的方法
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314756557声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
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