Posted in 面试题 onJanuary 25, 2013
将一个键盘输入的数字转化成中文输出
(例如:输入:1234567 输出:一百二拾三万四千五百六拾七)
用java语言实现,,请编一段程序实现!
1. public class Reader {
2. private String strNum;
3.
4. private String strNumChFormat;
5.
6. private String strNumTemp;
7.
8. private int intNumLen;
9.
10. private String strBegin;
11.
12. public Reader(String strNum) {
13. this.strNum = strNum;
14. }
15.
16. public boolean check(String strNum) {
17. boolean valid = false;
18. if (strNum.substring(0, 1).equals(“0″)) {
19. this.strNum = strNum.substring(1);
20. }
21. try {
22. new Double(strNum);
23. valid = true;
24. } catch (NumberFormatException ex) {
25. System.out.println(“Bad number format!”);
26. }
27. return valid;
28. }
29.
30. public void init() {
31. strNumChFormat = “”;
32. intNumLen = strNum.length();
33. strNumTemp = strNum;
34. strNumTemp = strNumTemp.replace(’1′, ‘一’);
35. strNumTemp = strNumTemp.replace(’2′, ‘二’);
36. strNumTemp = strNumTemp.replace(’3′, ‘三’);
37. strNumTemp = strNumTemp.replace(’4′, ‘四’);
38. strNumTemp = strNumTemp.replace(’5′, ‘五’);
39. strNumTemp = strNumTemp.replace(’6′, ‘六’);
40. strNumTemp = strNumTemp.replace(’7′, ‘七’);
41. strNumTemp = strNumTemp.replace(’8′, ‘八’);
42. strNumTemp = strNumTemp.replace(’9′, ‘九’);
43. strNumTemp = strNumTemp.replace(’0′, ‘零’);
44. strNumTemp = strNumTemp.replace(‘.’, ‘点’);
45. strBegin = strNumTemp.substring(0, 1);
46. }
47.
48. public String readNum() {
49. if (check(strNum)) {
50. init();
51. try {
52. for (int i = 1, j = 1, k = 1; i 53. if (strNumTemp.charAt(intNumLen – 1) == ‘零’ && i == 1) {
54. strNumChFormat = “位”;
55. } else if (strNumTemp.charAt(intNumLen – i) == ‘零’ && j == 1) {
56. strNumChFormat = “位” + strNumChFormat;
57. } else if (strNumTemp.charAt(intNumLen – i) == ‘点’) {
58. j = 1;
59. k = 1;
60. strNumChFormat = strNumTemp.charAt(intNumLen – i) + strNumChFormat;
61. continue;
62. } else {
63. strNumChFormat = strNumTemp.charAt(intNumLen – i) + strNumChFormat;
64. }
65. if (strNumTemp.charAt(intNumLen – i – 1) != ‘位’ && strNumTemp.charAt(intNumLen – i – 1) != ‘零’) {
66. if (j == 1 && i 67. strNumChFormat = ‘拾’ + strNumChFormat;
68. } else if (j == 2 && i 69. strNumChFormat = ‘百’ + strNumChFormat;
70. } else if (j == 3 && i 71. strNumChFormat = ‘千’ + strNumChFormat;
72. }
73. }
74. if (j == 4 && i 75. j = 0;
76. }
77. if (k == 4 && i 78. strNumChFormat = ‘万’ + strNumChFormat;
79. } else if (k == 8 && i 80. k = 0;
81. strNumChFormat = ‘亿’ + strNumChFormat;
82. }
83. j++;
84. k++;
85. }
86. while (strNumChFormat.indexOf(“位”) != -1) {
87. strNumChFormat = strNumChFormat.replaceAll(“位”, ” “);
88. }
89. if (strNumChFormat.substring(0, 2) == “一拾”) {
90. strNumChFormat = strNumChFormat.substring(1, strNumChFormat.length());
91. }
92. if (strNumChFormat.indexOf(“点”) >= 0) {
93. String rebegin = strNumChFormat.substring(0, strNumChFormat.indexOf(“点”));
94. String relast = strNumChFormat.substring(strNumChFormat.indexOf(“点”), strNumChFormat.length());
95. for (int i = 1; i 96. relast = relast.replaceAll(“拾”, “”);
97. relast = relast.replaceAll(“百”, “”);
98. relast = relast.replaceAll(“千”, “”);
99. relast = relast.replaceAll(“万”, “”);
100. relast = relast.replaceAll(“亿”, “”);
101. }
102. strNumChFormat = rebegin + relast;
103. }
104. } catch (ArrayIndexOutOfBoundsException ex) {
105. ex.printStackTrace();
106. } catch (Exception ex) {
107. ex.printStackTrace();
108. }
109. int off = strNumChFormat.indexOf(“点”);
110. strNumChFormat = strBegin + strNumChFormat.substring(0);
111. } else {
112. strNumChFormat = “”;
113. }
114. return strNumChFormat;
115. }
116.
117. public static void main(String args[]) {
118. try {
119. String number = args[0].toString();
120. System.out.println(“The number is: ” + number);
121. Reader reader = new Reader(number);
122. System.out.println(“Output String: ” + reader.readNum());
123. } catch (Exception ex) {
124. System.out.println(“Please input like that: javac Reader”);
125. }
126. }
127. }
(例如:输入:1234567 输出:一百二拾三万四千五百六拾七)
用java语言实现,,请编一段程序实现!
1. public class Reader {
2. private String strNum;
3.
4. private String strNumChFormat;
5.
6. private String strNumTemp;
7.
8. private int intNumLen;
9.
10. private String strBegin;
11.
12. public Reader(String strNum) {
13. this.strNum = strNum;
14. }
15.
16. public boolean check(String strNum) {
17. boolean valid = false;
18. if (strNum.substring(0, 1).equals(“0″)) {
19. this.strNum = strNum.substring(1);
20. }
21. try {
22. new Double(strNum);
23. valid = true;
24. } catch (NumberFormatException ex) {
25. System.out.println(“Bad number format!”);
26. }
27. return valid;
28. }
29.
30. public void init() {
31. strNumChFormat = “”;
32. intNumLen = strNum.length();
33. strNumTemp = strNum;
34. strNumTemp = strNumTemp.replace(’1′, ‘一’);
35. strNumTemp = strNumTemp.replace(’2′, ‘二’);
36. strNumTemp = strNumTemp.replace(’3′, ‘三’);
37. strNumTemp = strNumTemp.replace(’4′, ‘四’);
38. strNumTemp = strNumTemp.replace(’5′, ‘五’);
39. strNumTemp = strNumTemp.replace(’6′, ‘六’);
40. strNumTemp = strNumTemp.replace(’7′, ‘七’);
41. strNumTemp = strNumTemp.replace(’8′, ‘八’);
42. strNumTemp = strNumTemp.replace(’9′, ‘九’);
43. strNumTemp = strNumTemp.replace(’0′, ‘零’);
44. strNumTemp = strNumTemp.replace(‘.’, ‘点’);
45. strBegin = strNumTemp.substring(0, 1);
46. }
47.
48. public String readNum() {
49. if (check(strNum)) {
50. init();
51. try {
52. for (int i = 1, j = 1, k = 1; i 53. if (strNumTemp.charAt(intNumLen – 1) == ‘零’ && i == 1) {
54. strNumChFormat = “位”;
55. } else if (strNumTemp.charAt(intNumLen – i) == ‘零’ && j == 1) {
56. strNumChFormat = “位” + strNumChFormat;
57. } else if (strNumTemp.charAt(intNumLen – i) == ‘点’) {
58. j = 1;
59. k = 1;
60. strNumChFormat = strNumTemp.charAt(intNumLen – i) + strNumChFormat;
61. continue;
62. } else {
63. strNumChFormat = strNumTemp.charAt(intNumLen – i) + strNumChFormat;
64. }
65. if (strNumTemp.charAt(intNumLen – i – 1) != ‘位’ && strNumTemp.charAt(intNumLen – i – 1) != ‘零’) {
66. if (j == 1 && i 67. strNumChFormat = ‘拾’ + strNumChFormat;
68. } else if (j == 2 && i 69. strNumChFormat = ‘百’ + strNumChFormat;
70. } else if (j == 3 && i 71. strNumChFormat = ‘千’ + strNumChFormat;
72. }
73. }
74. if (j == 4 && i 75. j = 0;
76. }
77. if (k == 4 && i 78. strNumChFormat = ‘万’ + strNumChFormat;
79. } else if (k == 8 && i 80. k = 0;
81. strNumChFormat = ‘亿’ + strNumChFormat;
82. }
83. j++;
84. k++;
85. }
86. while (strNumChFormat.indexOf(“位”) != -1) {
87. strNumChFormat = strNumChFormat.replaceAll(“位”, ” “);
88. }
89. if (strNumChFormat.substring(0, 2) == “一拾”) {
90. strNumChFormat = strNumChFormat.substring(1, strNumChFormat.length());
91. }
92. if (strNumChFormat.indexOf(“点”) >= 0) {
93. String rebegin = strNumChFormat.substring(0, strNumChFormat.indexOf(“点”));
94. String relast = strNumChFormat.substring(strNumChFormat.indexOf(“点”), strNumChFormat.length());
95. for (int i = 1; i 96. relast = relast.replaceAll(“拾”, “”);
97. relast = relast.replaceAll(“百”, “”);
98. relast = relast.replaceAll(“千”, “”);
99. relast = relast.replaceAll(“万”, “”);
100. relast = relast.replaceAll(“亿”, “”);
101. }
102. strNumChFormat = rebegin + relast;
103. }
104. } catch (ArrayIndexOutOfBoundsException ex) {
105. ex.printStackTrace();
106. } catch (Exception ex) {
107. ex.printStackTrace();
108. }
109. int off = strNumChFormat.indexOf(“点”);
110. strNumChFormat = strBegin + strNumChFormat.substring(0);
111. } else {
112. strNumChFormat = “”;
113. }
114. return strNumChFormat;
115. }
116.
117. public static void main(String args[]) {
118. try {
119. String number = args[0].toString();
120. System.out.println(“The number is: ” + number);
121. Reader reader = new Reader(number);
122. System.out.println(“Output String: ” + reader.readNum());
123. } catch (Exception ex) {
124. System.out.println(“Please input like that: javac Reader
125. }
126. }
127. }
用Java语言将一个键盘输入的数字转化成中文输出
声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
Tags in this post...
Reply on: @reply_date@
@reply_contents@