Posted in Python onNovember 11, 2014
本文实例讲述了python获取文件后缀名及批量更新目录下文件后缀名的方法。分享给大家供大家参考。具体实现方法如下:
1. 获取文件后缀名:
#!/usr/bin/python import os dict = {} for d, fd, fl in os.walk('/home/ahda/Program/'): for f in fl: sufix = os.path.splitext(f)[1][1:] if dict.has_key(sufix): dict[sufix] += 1 else: dict[sufix] = 1 for item in dict.items(): print "%s : %s" % item
这里的关键是os.path.splitext()
如abc/ef.g.h ,这里获取到的是h
2. python查找遍历指定文件路径下指定后缀名的文件实例:
import os import sys import os.path for dirpath, dirnames, filenames in os.walk(startdir): for filename in filenames: if os.path.splitext(filename)[1] == '.txt': filepath = os.path.join(dirpath, filename) #print("file:" + filepath) input_file = open(filepath) text = input_file.read() input_file.close() output_file = open( filepath, 'w') output_file.write(text) output_file.close()
3. 批量重命名目录中的文件后缀实例:
import os def swap_extensions(dir, before, after): if before[:1] != '.': #如果参数中的后缀名没有'.'则加上 before = '.' + before thelen = -len(before) if after[:1] != '.': after = '.' + after for path, subdir, files in os.walk(dir): for oldfile in files: if oldfile[thelen:] == before: oldfile = os.path.join(path, oldfile) newfile = oldfile[:thelen] + after os.rename(oldfile, newfile) print oldfile +' changed to ' + newfile if __name__ == '__main__': import sys if len(sys.argv) != 4: print 'Usage:swap_extension.py rootdir before after' sys.exit(1) swap_extensions(sys.argv[1], sys.argv[2], sys.argv[3])
例子:将e:/py/test目录下.php结尾的文件重命名为.py
E:py>python_cook e:/py/test .php .py
e:/py/testtest.php changed to e:/py/testtest.py
e:/py/test1.php changed to e:/py/test1.py
e:/py/test2.php changed to e:/py/test2.py
希望本文所述对大家的Python程序设计有所帮助。
python获取文件后缀名及批量更新目录下文件后缀名的方法
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shichen2014声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
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