Posted in Javascript onSeptember 15, 2015
本文实例讲述了JS实现仿FLASH效果的竖排导航代码。分享给大家供大家参考。具体如下:
这是一款JS+CSS实现的Flash效果的导航菜单,竖向排列,兼容性好,由JavaScript妙味课堂的朋友编写,欢迎测试.
运行效果截图如下:
在线演示地址如下:
具体代码如下:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>仿FLASH的竖排导航</title> <style> li { margin-bottom: 2px; list-style: none; background: url(images/bg.gif) repeat-x 0 1px; float: left; clear: left; cursor: pointer-; } a { display: block; width: 120px; height: 25px; line-height: 25px; position: relative; padding: 0 6px; border: 1px solid #d6d6d6; text-decoration: none; font-size: 12px; color: #555; } a:hover { font-weight: bold; border: 1px solid #b5b5b5; } span { display: block; width: 9px; height: 8px; overflow: hidden; background: url(images/ico.gif) no-repeat; position: absolute; top: 8px; right: 10px; } </style> <script type="text/javascript"> window.onload=function () { var aA=document.getElementById('menu').getElementsByTagName('a'); var i=0; for(i=0;i<aA.length;i++) { aA[i].iTime=null; aA[i].iSpeed=6; aA[i].onmouseover=function () { goTime(this,30,1); } aA[i].onmouseout=function () { goTime(this,6,-1); } } } function goTime(obj,iTarget,toggle) { if(obj.iTime) { clearInterval(obj.iTime); } obj.iTime=setInterval(function() { if(obj.iSpeed===iTarget) { clearInterval(obj.iTime); obj.iTime=null; } else { obj.iSpeed+=2*toggle; obj.style.paddingLeft=obj.iSpeed+'px'; obj.style.paddingRight=obj.iSpeed+'px'; } },30); } </script> </head> <body> <ul id="menu"> <li><a href="#" target="_blank">首页<span></span></a></li> <li><a href="#" target="_blank">网页特效<span></span></a></li> <li><a href="#" target="_blank">CSS相关知识<span></span></a></li> <li><a href="#" target="_blank">关于我们<span></span></a></li> <li><a href="#" target="_blank">联系我们<span></span></a></li> </ul> </body> </html>
希望本文所述对大家的JavaScript程序设计有所帮助。
JS实现仿FLASH效果的竖排导航代码
- Author -
企鹅声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
Reply on: @reply_date@
@reply_contents@