使用JavaScript实现node.js中的path.join方法

Node.JS中的 path.join 非常方便，能直接按相对或绝对合并路径，使用： path.join([path1], [path2], [...])，有时侯前端也需要这种方法，如何实现呢？

其实直接从 node.js 的 path.js 拿到源码加工一下就可以了：

1. 将 const 等 es6 属性改为 var，以便前端浏览器兼容
2. 添加一个判断路戏分隔符的变量 sep，即左斜杠还是右斜杠，以第一个路戏分隔符为准
3. 将引用的变量和函数放到一个文件里就可以了：

Path 的源码： https://github.com/nodejs/node/blob/master/lib/path.js

var CHAR_FORWARD_SLASH = 47
var CHAR_BACKWARD_SLASH = 92
var CHAR_DOT = 46
function isPathSeparator(code) {
 return code === CHAR_FORWARD_SLASH || code === CHAR_BACKWARD_SLASH;
}
function isPosixPathSeparator(code) {
 return code === CHAR_FORWARD_SLASH;
}
function normalize(path) {
 if (path.length === 0)
  return '.';
 var isAbsolute = path.charCodeAt(0) === CHAR_FORWARD_SLASH;
 var trailingSeparator =
  path.charCodeAt(path.length - 1) === CHAR_FORWARD_SLASH;
 // Normalize the path
 path = normalizeString(path, !isAbsolute, '/', isPosixPathSeparator);
 if (path.length === 0 && !isAbsolute)
  path = '.';
 if (path.length > 0 && trailingSeparator)
  path += '/';
 if (isAbsolute)
  return '/' + path;
 return path;
}
function normalizeString(path, allowAboveRoot, separator, isPathSeparator) {
 var res = '';
 var lastSegmentLength = 0;
 var lastSlash = -1;
 var dots = 0;
 var code;
 for (var i = 0; i <= path.length; ++i) {
  if (i < path.length)
   code = path.charCodeAt(i);
  else if (isPathSeparator(code))
   break;
  else
   code = CHAR_FORWARD_SLASH;
  if (isPathSeparator(code)) {
   if (lastSlash === i - 1 || dots === 1) {
    // NOOP
   } else if (lastSlash !== i - 1 && dots === 2) {
    if (res.length < 2 || lastSegmentLength !== 2 ||
      res.charCodeAt(res.length - 1) !== CHAR_DOT ||
      res.charCodeAt(res.length - 2) !== CHAR_DOT) {
     if (res.length > 2) {
      const lastSlashIndex = res.lastIndexOf(separator);
      if (lastSlashIndex !== res.length - 1) {
       if (lastSlashIndex === -1) {
        res = '';
        lastSegmentLength = 0;
       } else {
        res = res.slice(0, lastSlashIndex);
        lastSegmentLength = res.length - 1 - res.lastIndexOf(separator);
       }
       lastSlash = i;
       dots = 0;
       continue;
      }
     } else if (res.length === 2 || res.length === 1) {
      res = '';
      lastSegmentLength = 0;
      lastSlash = i;
      dots = 0;
      continue;
     }
    }
    if (allowAboveRoot) {
     if (res.length > 0)
      res += `${separator}..`;
     else
      res = '..';
     lastSegmentLength = 2;
    }
   } else {
    if (res.length > 0)
     res += separator + path.slice(lastSlash + 1, i);
    else
     res = path.slice(lastSlash + 1, i);
    lastSegmentLength = i - lastSlash - 1;
   }
   lastSlash = i;
   dots = 0;
  } else if (code === CHAR_DOT && dots !== -1) {
   ++dots;
  } else {
   dots = -1;
  }
 }
 return res;
}
function join() {
 if (arguments.length === 0)
  return '.';
 var sep = arguments[0].indexOf('/') > -1 ? '/' : '\\'
 var joined;
 var firstPart;
 for (var i = 0; i < arguments.length; ++i) {
  var arg = arguments[i];
  if (arg.length > 0) {
   if (joined === undefined)
    joined = firstPart = arg;
   else
    joined += sep + arg;
  }
 }
 if (joined === undefined)
  return '.';
 var needsReplace = true;
 var slashCount = 0;
 if (isPathSeparator(firstPart.charCodeAt(0))) {
  ++slashCount;
  var firstLen = firstPart.length;
  if (firstLen > 1) {
   if (isPathSeparator(firstPart.charCodeAt(1))) {
    ++slashCount;
    if (firstLen > 2) {
     if (isPathSeparator(firstPart.charCodeAt(2)))
      ++slashCount;
     else {
      // We matched a UNC path in the first part
      needsReplace = false;
     }
    }
   }
  }
 }
 if (needsReplace) {
  // Find any more consecutive slashes we need to replace
  for (; slashCount < joined.length; ++slashCount) {
   if (!isPathSeparator(joined.charCodeAt(slashCount)))
    break;
  }
  // Replace the slashes if needed
  if (slashCount >= 2)
   joined = sep + joined.slice(slashCount);
 }
 return normalize(joined);
}

使用：

join('../var/www', '../abc')
> "../var/abc"
join('../var/www', '\abc')
../var/www/abc

总结

以上所述是小编给大家介绍的使用JavaScript实现node.js中的path.join方法，希望对大家有所帮助，如果对大家有所帮助，如果大家有任何疑问欢迎给我留言，小编会及时回复大家的！