jQuery each()小议

var arr1 = [ "one", "two", "three", "four", "five" ]; 
$.each(arr1, function(){ 
alert(this); 
});

输出：one two three four five

var arr2 = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] 
$.each(arr2, function(i, item){ 参数的名字可以自己定义，each方法会根据第一个参数(arr2)的格式而判断回调函数方法体语法的正确性 
alert(item[0]); 
});

输出：1 4 7

var obj = { one:1, two:2, three:3, four:4, five:5 }; 
$.each(obj, function(key, val) { 
alert(obj[key]); 
});

输出：1 2 3 4 5

$.each($("input:hidden"), function(){ 
alert(this.name); 
}); 
$.each($("input:hidden"), function(){ 
alert(this.value); 
});

跳出遍历

$(document).ready( 
function test() 
{ var index=0; 
var arr1 = [[1, 4, 3], [4, 6, 6], [7, 20, 9]] 
$.each(arr1, function(i,item){ 
if(i==1) 
{ 
alert("点击继续下次遍历"); 
return ; //return false ;则跳出遍历 
} 
alert('索引'+i+'_'+item[0]); 
}); 
})