Posted in PHP onJanuary 28, 2015
本文实例讲述了php+mysqli实现将数据库中一张表信息(包括表头)打印到表格里的方法。分享给大家供大家参考。具体如下:
这段代码将就看吧。需要学习基础知识。代码如下:
<?php $mysqli = new MySQLi("localhost","root","123456","liuyan"); if(!$mysqli){ die($mysqli->error); } function showTable($mysqli,$table_name){ $sql = "select * from $table_name"; $res = $mysqli->query($sql); //获取返回总行数和列数 echo "共有:".$res->num_rows."行;共有:".$res->field_count."列。"; //获取表头---从$res取出 echo "<table border=1><tr>"; while($field=$res->fetch_field()){ echo "<th>{$field->name}</th>"; } echo "</tr>"; //循环取出数据 while($row=$res->fetch_row()){ echo "<tr>"; foreach($row as $value){ echo "<td>$value</td>"; } echo "</tr>"; } echo "</table>"; $res->free(); } showTable($mysqli,"news"); ?>
希望本文所述对大家的php程序设计有所帮助。
php+mysqli实现将数据库中一张表信息打印到表格里的方法
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shichen2014声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
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