Posted in Python onFebruary 14, 2014
def insertion_sort(n): if len(n) == 1: return n b = insertion_sort(n[1:]) m = len(b) for i in range(m): if n[0] <= b[i]: return b[:i]+[n[0]]+b[i:] return b + [n[0]] l = [1,3,4,2,6,7,9,7,12,11,789,345,456] print insertion_sort(l) d = input('l=') print insertion_sort(d) a = input('y:')
python实现排序算法
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