Posted in Python onApril 22, 2020
本文实例为大家分享了python实现扑克牌交互式界面发牌程序的具体代码,供大家参考,具体内容如下
注:图片自行在网上下载、替换即可
#coding=utf-8 class Card(): #扑克牌类 points=['1','2','3','4','5','6','7','8','9','10','11','12','13'] suits=['1','2','3','4'] #花色 def __init__(self,points,suits): self.points=points self.suits=suits def __str__(self): rep=self.suits+'-'+self.points return rep class Hand(): def __init__(self): self.cards=[] def add(self,card): self.cards.append(card) def __str__(self): rep='' for card in self.cards: rep+=str(card)+'\t' return rep class Poke(Hand): def generate_poke(self): for point in Card.points: for suit in Card.suits: self.add(Card(point,suit)) def random_poke(self): import random random.shuffle(self.cards) def deal(self,hands,limit_hand=13): for rounds in range (limit_hand): for hand in hands: if self.cards: top=self.cards[0] self.cards.remove(top) hand.add(top) def print_poke(players): results=[player.__str__() for player in players] pk=[] for result in results: pk1=result.rstrip() pk2=pk1.split('\t') pk.append(pk2) image_name=[] for i in range(len(pk)): for j in pk[i]: str_name='D:\pukepai\images\\{}.gif'.format(j) image_name.append(str_name) wj=[image_name[i:i+13] for i in range(len(image_name)) if i%13==0] return wj def restart(): tk.messagebox.showinfo("hello python","sdfg") players=[Hand(),Hand(),Hand(),Hand()] pockers=Poke() pockers.generate_poke() pockers.random_poke() pockers.deal(players,13) wj=print_poke(players) import tkinter as tk win=tk.Tk() win.title("扑克牌程序") win.geometry('800x600') cv=tk.Canvas(win,bg='red',width=800,height=600) from PIL import Image,ImageTk imgs=[] (p1,p2,p3,p4)=([],[],[],[]) for i in range(4): for j in range(13): img=Image.open(wj[i][j]) imgs.insert(i*13+j,ImageTk.PhotoImage(img)) p1=imgs[0:13] p2=imgs[13:26] p3=imgs[26:39] p4=imgs[39:52] for x in range(0,13): cv.create_image((200+20*x,80),image=p1[x]) cv.create_image((100,150+20*x),image=p2[x]) cv.create_image((200+20*x,500),image=p3[x]) cv.create_image((560,150+20*x),image=p4[x]) #添加重新发牌按钮 from tkinter.messagebox import * bt1=tk.Button(win,text='重新发牌',width=60,height=40,command=restart) bt1.place(x=290,y=380,width=60,height=40) cv.pack() win.mainloop()
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持三水点靠木。
python实现扑克牌交互式界面发牌程序
- Author -
Yu_X_Q声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
Reply on: @reply_date@
@reply_contents@