Posted in PHP onDecember 06, 2016
本文实例讲述了php简单计算年龄的方法。分享给大家供大家参考,具体如下:
/** * $date是时间戳 * $type为1的时候是虚岁,2的时候是周岁 */ function getAgeByBirth($date,$type = 1){ $nowYear = date("Y",time()); $nowMonth = date("m",time()); $nowDay = date("d",time()); $birthYear = date("Y",$date); $birthMonth = date("m",$date); $birthDay = date("d",$date); if($type == 1){ $age = $nowYear - ($birthYear - 1); }else{$type == 2}{ if($nowMonth<$birthMonth){ $age = $nowYear - $birthYear - 1; }elseif($nowMonth==$birthMonth){ if($nowDay<$birthDay){ $age = $nowYear - $birthYear - 1; }else{ $age = $nowYear - $birthYear; } }else{ $age = $nowYear - $birthYear; } } return $age; }
PS:本站还提供了一个Unix时间戳转换工具,包含了各种常见语言针对时间戳的操作方法,提供给大家参考:
Unix时间戳(timestamp)转换工具:
http://tools.3water.com/code/unixtime
希望本文所述对大家PHP程序设计有所帮助。
php简单计算年龄的方法(周岁与虚岁)
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