PHP提取数据库内容中的图片地址并循环输出

/* 
1 (?s) 代表 Pattern.DOTALL,也就是匹配换行，允许 img里出现在多行 
2 .*?代表非贪婪匹配任意字符，直到后面的条件出现 
3 ?: 代表这个匹配但不被捕获，也就是不在结果出现 [\.gif|\.jpg] 是或者的意思 
*/ 
$pattern="/<img.*?src=[\'|\"](.*?(?:[\.gif|\.jpg]))[\'|\"].*?[\/]?>/"; 
$str='<p style="padding: 0px; margin-top: 0px; margin-bottom: 0px; line-height: 200%;"><img border="0" src="upfiles/2009/07/1246430143_4.jpg" alt=""/></p><p style="padding: 0px; margin-top: 0px; margin-bottom: 0px; line-height: 200%;"><img border="0" src="upfiles/2009/07/1246430143_3.jpg" alt=""/></p><p style="padding: 0px; margin-top: 0px; margin-bottom: 0px; line-height: 200%;"><img border="0" src="upfiles/2009/07/1246430143_1.jpg" alt=""/></p>'; 
preg_match_all($pattern,$str,$match); 
print_r($match); 
/* 
Array 
( 
[0] => Array 
( 
[0] => <img border="0" src="upfiles/2009/07/1246430143_4.jpg" alt=""/> 
[1] => <img border="0" src="upfiles/2009/07/1246430143_3.jpg" alt=""/> 
[2] => <img border="0" src="upfiles/2009/07/1246430143_1.jpg" alt=""/> 
) 
[1] => Array 
( 
[0] => upfiles/2009/07/1246430143_4.jpg 
[1] => upfiles/2009/07/1246430143_3.jpg 
[2] => upfiles/2009/07/1246430143_1.jpg 
) 
) 
*/