Posted in Javascript onMarch 11, 2015
本文实例讲述了jQuery处理json数据返回数组和输出的方法。分享给大家供大家参考。具体实现方法如下:
/*print the json object * *$("selector").print_r_json(json,opts) : return formatted string (and print) *sprint_r_json : just return the string; *print_r_json : return the formatted string and print json data *contribute 明河 * *auth iorichina * *example: *3 ways to use it *<script language="javascript"> *$("selector").print_r_json({"a":"aa","d":{"ef":{"a":"d","d":["a","b"]},"ed":"dd"},"g":"g"},{if_print:true,return_array:true}); *document.write($.sprint_r_json({"a":"aa","d":{"ef":{"a":"d","d":["a","b"]},"ed":"dd"},"g":"g"})); *$.print_r_json({"a":"aa","d":{"ef":{"a":"d","d":["a","b"]},"ed":"dd"},"g":"g"}); *</script> * */ $.fn.print_r_json = function(json,options){ if(typeof(json)!="object") return false; var opts = $.extend({},$.fn.print_r_json.defaults,options); var data = ''; if(opts.if_print) { data = $.sprint_r_json(json) $(this).html('<div style="font-weight:bold">'+(opts.return_array?'Array':'JSON-DATA')+'</div>'+data); } if(opts.array) { return $.json_to_array(json); } return data; }; $.fn.print_r_json.defaults = { if_print : false,//if print or just return formatted string return_array : true //return an Array }; $.extend({ print_r_json : function(json) { if(typeof(json)=="object") { var text='<div style="font-weight:bold;">{</div><div style="margin-left:25px;">'; document.write('<div style="font-weight:bold;">{</div><div style="margin-left:25px;">'); for(var p in json) { if(typeof(json[p])=="object") { document.write('<div>["'+p+'"] => '); text+='<div>["'+p+'"] => '+$.print_r_json(json[p])+'</div>'; document.write('</div>'); } else { text+='<div>['+((/^\d+$/).test(p)?p:('"'+p+'"'))+'] => "'+json[p]+'"</div>'; document.write('<div>['+p+'] => '+json[p]+'</div>'); } } text+='</div><div style="font-weight:bold;">}</div>'; document.write('</div><div style="font-weight:bold;">}</div>'); return (text); } else { document.write(json); return (json); } }, sprint_r_json : function(json) { if(typeof(json)=="object") { var text = '<div style="font-weight:bold;">{</div><div style="margin-left:25px;">'; for(var p in json) { if(typeof(json[p])=="object") { text += '<div>["'+p+'"] => '+$.sprint_r_json(json[p])+'</div>'; } else { text += '<div>['+((/^\d+$/).test(p)?p:('"'+p+'"'))+'] => "'+json[p]+'"</div>'; } } text += '</div><div style="font-weight:bold;">}</div>'; return (text); } else { return (json); } }, json_to_array : function(json) { if(typeof(json)=="object") { var text = new Array(); for(var p in json) { if(typeof(json[p])=="object") { text[p] = $.json_to_array(json[p]); } else { text[p] = json[p]; } } return (text); } else { return (json); } } });
希望本文所述对大家的jQuery程序设计有所帮助。
jQuery处理json数据返回数组和输出的方法
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iorichina声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
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