Posted in Python onFebruary 06, 2020
本文实例讲述了python时间日期操作方法。分享给大家供大家参考,具体如下:
#coding=utf-8 import time import datetime if __name__ == "__main__": # 今天 now = datetime.datetime.now() print now.strftime('%Y-%m-%d %H:%M:%S') print "%s-%s-%s %s:%s:%s" % (now.year, now.month, now.day, now.hour, now.minute, now.second) print time.strftime("%Y-%m-%d %H:%M:%S", time.localtime()) # 前一天 now = datetime.datetime.now() dt = now + datetime.timedelta(days=-1) print dt.strftime('%Y-%m-%d %H:%M:%S') print time.strftime("%Y-%m-%d %H:%M:%S", time.localtime(time.time() - 24 * 3600)) # 后一天 now = datetime.datetime.now() dt = now + datetime.timedelta(days=1) print dt.strftime('%Y-%m-%d %H:%M:%S') print time.strftime("%Y-%m-%d %H:%M:%S", time.localtime(time.time() + 24 * 3600)) # 前一小时 now = datetime.datetime.now() dt = now - datetime.timedelta(hours=1) print dt.strftime("%Y-%m-%d %H:%M:%S") print time.strftime("%Y-%m-%d %H:%M:%S", time.localtime(time.time() - 1 * 3600)) # 时间戳 秒 print int(time.time()) # 时间戳 毫秒 print int(round(time.time() * 1000)) # 时间戳 to 日期 print datetime.datetime.fromtimestamp(1507630854) print time.strftime("%Y-%m-%d %H:%M:%S", time.localtime(1507630854)) print time.strftime("%Y-%m-%d %H:%M:%S", time.localtime()) # 日期 to 时间戳 print time.mktime(time.strptime("2017-10-10", "%Y-%m-%d")) print time.mktime(time.strptime("2017-10-10 10:10:10", "%Y-%m-%d %H:%M:%S"))
运行结果:
2020-02-06 11:33:51
2020-2-6 11:33:51
2020-02-06 11:33:51
2020-02-05 11:33:51
2020-02-05 11:33:51
2020-02-07 11:33:51
2020-02-07 11:33:51
2020-02-06 10:33:51
2020-02-06 10:33:51
1580960031
1580960031893
2017-10-10 18:20:54
2017-10-10 18:20:54
2020-02-06 11:33:51
1507564800.0
1507601410.0
PS:这里再为大家推荐几款关于日期与天数计算的在线工具供大家使用:
在线日期/天数计算器:
http://tools.3water.com/jisuanqi/date_jisuanqi
在线万年历日历:
http://tools.3water.com/bianmin/wannianli
在线阴历/阳历转换工具:
http://tools.3water.com/bianmin/yinli2yangli
Unix时间戳(timestamp)转换工具:
http://tools.3water.com/code/unixtime
希望本文所述对大家Python程序设计有所帮助。
python时间日期操作方法实例小结
- Author -
李琼涛声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
Reply on: @reply_date@
@reply_contents@