Posted in Python onApril 24, 2020
上篇博文我们实现了两百行代码实现贪吃蛇游戏,这次我们来实现一个代码量更加少,功能却更加完整的
python代码实现贪吃蛇游戏,具体代码与文件可以访问我的GitHub地址获取
游戏截图
动图
贪吃蛇python代码
"""贪吃蛇""" import random import sys import time import pygame from pygame.locals import * from collections import deque SCREEN_WIDTH = 600 # 屏幕宽度 SCREEN_HEIGHT = 480 # 屏幕高度 SIZE = 20 # 小方格大小 LINE_WIDTH = 1 # 网格线宽度 # 游戏区域的坐标范围 SCOPE_X = (0, SCREEN_WIDTH // SIZE - 1) SCOPE_Y = (2, SCREEN_HEIGHT // SIZE - 1) # 食物的分值及颜色 FOOD_STYLE_LIST = [(10, (255, 100, 100)), (20, (100, 255, 100)), (30, (100, 100, 255))] LIGHT = (100, 100, 100) DARK = (200, 200, 200) # 蛇的颜色 BLACK = (0, 0, 0) # 网格线颜色 RED = (200, 30, 30) # 红色,GAME OVER 的字体颜色 BGCOLOR = (40, 40, 60) # 背景色 def print_text(screen, font, x, y, text, fcolor=(255, 255, 255)): imgText = font.render(text, True, fcolor) screen.blit(imgText, (x, y)) # 初始化蛇 def init_snake(): snake = deque() snake.append((2, SCOPE_Y[0])) snake.append((1, SCOPE_Y[0])) snake.append((0, SCOPE_Y[0])) return snake def create_food(snake): food_x = random.randint(SCOPE_X[0], SCOPE_X[1]) food_y = random.randint(SCOPE_Y[0], SCOPE_Y[1]) while (food_x, food_y) in snake: # 如果食物出现在蛇身上,则重来 food_x = random.randint(SCOPE_X[0], SCOPE_X[1]) food_y = random.randint(SCOPE_Y[0], SCOPE_Y[1]) return food_x, food_y def get_food_style(): return FOOD_STYLE_LIST[random.randint(0, 2)] def main(): pygame.init() screen = pygame.display.set_mode((SCREEN_WIDTH, SCREEN_HEIGHT)) pygame.display.set_caption('贪吃蛇') font1 = pygame.font.SysFont('SimHei', 24) # 得分的字体 font2 = pygame.font.Font(None, 72) # GAME OVER 的字体 fwidth, fheight = font2.size('GAME OVER') # 如果蛇正在向右移动,那么快速点击向下向左,由于程序刷新没那么快,向下事件会被向左覆盖掉,导致蛇后退,直接GAME OVER # b 变量就是用于防止这种情况的发生 b = True # 蛇 snake = init_snake() # 食物 food = create_food(snake) food_style = get_food_style() # 方向 pos = (1, 0) game_over = True start = False # 是否开始,当start = True,game_over = True 时,才显示 GAME OVER score = 0 # 得分 orispeed = 0.5 # 原始速度 speed = orispeed last_move_time = None pause = False # 暂停 while True: for event in pygame.event.get(): if event.type == QUIT: sys.exit() elif event.type == KEYDOWN: if event.key == K_RETURN: if game_over: start = True game_over = False b = True snake = init_snake() food = create_food(snake) food_style = get_food_style() pos = (1, 0) # 得分 score = 0 last_move_time = time.time() elif event.key == K_SPACE: if not game_over: pause = not pause elif event.key in (K_w, K_UP): # 这个判断是为了防止蛇向上移时按了向下键,导致直接 GAME OVER if b and not pos[1]: pos = (0, -1) b = False elif event.key in (K_s, K_DOWN): if b and not pos[1]: pos = (0, 1) b = False elif event.key in (K_a, K_LEFT): if b and not pos[0]: pos = (-1, 0) b = False elif event.key in (K_d, K_RIGHT): if b and not pos[0]: pos = (1, 0) b = False # 填充背景色 screen.fill(BGCOLOR) # 画网格线 竖线 for x in range(SIZE, SCREEN_WIDTH, SIZE): pygame.draw.line(screen, BLACK, (x, SCOPE_Y[0] * SIZE), (x, SCREEN_HEIGHT), LINE_WIDTH) # 画网格线 横线 for y in range(SCOPE_Y[0] * SIZE, SCREEN_HEIGHT, SIZE): pygame.draw.line(screen, BLACK, (0, y), (SCREEN_WIDTH, y), LINE_WIDTH) if not game_over: curTime = time.time() if curTime - last_move_time > speed: if not pause: b = True last_move_time = curTime next_s = (snake[0][0] + pos[0], snake[0][1] + pos[1]) if next_s == food: # 吃到了食物 snake.appendleft(next_s) score += food_style[0] speed = orispeed - 0.03 * (score // 100) food = create_food(snake) food_style = get_food_style() else: if SCOPE_X[0] <= next_s[0] <= SCOPE_X[1] and SCOPE_Y[0] <= next_s[1] <= SCOPE_Y[1] \ and next_s not in snake: snake.appendleft(next_s) snake.pop() else: game_over = True # 画食物 if not game_over: # 避免 GAME OVER 的时候把 GAME OVER 的字给遮住了 pygame.draw.rect(screen, food_style[1], (food[0] * SIZE, food[1] * SIZE, SIZE, SIZE), 0) # 画蛇 for s in snake: pygame.draw.rect(screen, DARK, (s[0] * SIZE + LINE_WIDTH, s[1] * SIZE + LINE_WIDTH, SIZE - LINE_WIDTH * 2, SIZE - LINE_WIDTH * 2), 0) print_text(screen, font1, 30, 7, f'速度: {score//100}') print_text(screen, font1, 450, 7, f'得分: {score}') if game_over: if start: print_text(screen, font2, (SCREEN_WIDTH - fwidth) // 2, (SCREEN_HEIGHT - fheight) // 2, 'GAME OVER', RED) pygame.display.update() if __name__ == '__main__': main()
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150行python代码实现贪吃蛇游戏
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