python实现在图片上画特定大小角度矩形框

做图像识别的时候需要在图片中画出特定大小和角度的矩形框，自己写了一个函数，给定的输入是图片名称，矩形框的位置坐标,长宽和角度，直接输出画好矩形框的图片。

主要思想是先根据x,y坐标和长宽得到矩形，然后通过数学计算得到旋转angle角度后的新矩形框的四个顶点位置坐标，再利用draw.line()函数画出来。

import math

import matplotlib.pyplot as plt
import numpy as np
from PIL import Image, ImageDraw


def draw(filename,result):
  img = Image.open(filename)
  w,h=img.size
  draw = ImageDraw.Draw(img)
  result=np.array(result)
  x=result[0][0]
  y=result[0][1]
  angle=result[0][2]
  height=result[0][3]
  width=result[0][4]

  anglePi = -angle*math.pi/180.0
  cosA = math.cos(anglePi)
  sinA = math.sin(anglePi)

  x1=x-0.5*width
  y1=y-0.5*height

  x0=x+0.5*width
  y0=y1

  x2=x1
  y2=y+0.5*height

  x3=x0
  y3=y2

  x0n= (x0 -x)*cosA -(y0 - y)*sinA + x
  y0n = (x0-x)*sinA + (y0 - y)*cosA + y

  x1n= (x1 -x)*cosA -(y1 - y)*sinA + x
  y1n = (x1-x)*sinA + (y1 - y)*cosA + y

  x2n= (x2 -x)*cosA -(y2 - y)*sinA + x
  y2n = (x2-x)*sinA + (y2 - y)*cosA + y

  x3n= (x3 -x)*cosA -(y3 - y)*sinA + x
  y3n = (x3-x)*sinA + (y3 - y)*cosA + y


  draw.line([(x0n, y0n),(x1n, y1n)], fill=(0, 0, 255))
  draw.line([(x1n, y1n),(x2n, y2n)], fill=(255, 0, 0))
  draw.line([(x2n, y2n),(x3n, y3n)],fill= (0,0,255))
  draw.line([(x0n, y0n), (x3n, y3n)],fill=(255,0,0))

  plt.imshow(img)
  plt.show()

改写成c++

由于c++程序也需要用到这个程序，改写一下

void CopentestDlg::OnBnClickedAnaly()
{
  CString x,y,angle,width;
  float xRaw[4], yRaw[4];
  float xNew[4], yNew[4];
  float height = 33;
  if (imageCut==NULL) {
    AfxMessageBox(_T("未打开图片不能分析"));
    return;
  }
  GetDlgItem(IDC_EX)->GetWindowText(x);
  GetDlgItem(IDC_EY)->GetWindowText(y);
  GetDlgItem(IDC_ANGLE)->GetWindowText(angle);
  GetDlgItem(IDC_WIDTH)->GetWindowText(width);
  float xf = _tstof(x); //将Cstring转成float类型
  float yf = _tstof(y);
  float widthf= _tstof(width);
  float anglef= _tstof(angle);

  xRaw[1] = xf - 0.5*widthf;
  yRaw[1] = yf - 0.5*height;

  xRaw[0] = xf + 0.5*widthf;
  yRaw[0] = yRaw[1];

  xRaw[2] = xRaw[1];
  yRaw[2] = yf + 0.5*height;

  xRaw[3] = xRaw[0];
  yRaw[3] = yRaw[2];

  float anglePi = -anglef*pi / 180.0;
  float cosA = cos(anglePi);
  float sinA = sin(anglePi);

  xNew[0] = (xRaw[0] - xf)*cosA - (yRaw[0] - yf)*sinA + xf;
  yNew[0] = (xRaw[0] - xf)*sinA + (yRaw[0] - yf)*cosA + yf;

  xNew[1] = (xRaw[1] - xf)*cosA - (yRaw[1] - yf)*sinA + xf;
  yNew[1] = (xRaw[1] - xf)*sinA + (yRaw[1] - yf)*cosA + yf;

  xNew[2] = (xRaw[2] - xf)*cosA - (yRaw[2] - yf)*sinA + xf;
  yNew[2] = (xRaw[2] - xf)*sinA + (yRaw[2] - yf)*cosA + yf;

  xNew[3] = (xRaw[3] - xf)*cosA - (yRaw[3] - yf)*sinA + xf;
  yNew[3] = (xRaw[3] - xf)*sinA + (yRaw[3] - yf)*cosA + yf;

  cvLine(imageCut, cvPoint(xNew[0], yNew[0]), cvPoint(xNew[1], yNew[1]), cvScalar(0, 0, 255), 3);
  cvLine(imageCut, cvPoint(xNew[1], yNew[1]), cvPoint(xNew[2], yNew[2]), cvScalar(255, 0, 0), 3);
  cvLine(imageCut, cvPoint(xNew[2], yNew[2]), cvPoint(xNew[3], yNew[3]), cvScalar(0, 0, 255), 3);
  cvLine(imageCut, cvPoint(xNew[0], yNew[0]), cvPoint(xNew[3], yNew[3]), cvScalar(255, 0, 0), 3);

  DrawPicToHDC(imageCut, IDC_Cut);
  pEdit->ReplaceSel(_T("图片已修改\r\n"));
}

效果图

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持三水点靠木。