Posted in Python onMay 04, 2018
方法一:回归实现
def PowerSetsRecursive(items): """Use recursive call to return all subsets of items, include empty set""" if len(items) == 0: #if the lsit is empty, return the empty list return [[]] subsets = [] first_elt = items[0] #first element rest_list = items[1:] #Strategy:Get all subsets of rest_list; for each of those subsets, a full subset list #will contain both the original subset as well as a version of the sebset that contains the first_elt for partial_sebset in PowerSetsRecursive(rest_list): subsets.append(partial_sebset) next_subset = partial_sebset[:] +[first_elt] subsets.append(next_subset) return subsets
def PowerSetsRecursive2(items): # the power set of the empty set has one element, the empty set result = [[]] for x in items: result.extend([subset + [x] for subset in result]) return result
方法二:二进制法
def PowerSetsBinary(items): #generate all combination of N items N = len(items) #enumerate the 2**N possible combinations for i in range(2**N): combo = [] for j in range(N): #test jth bit of integer i if(i >> j ) % 2 == 1: combo.append(items[j]) yield combo
以上这篇Python实现求一个集合所有子集的示例就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持三水点靠木。
Python实现求一个集合所有子集的示例
- Author -
tszw1007声明:登载此文出于传递更多信息之目的,并不意味着赞同其观点或证实其描述。
Reply on: @reply_date@
@reply_contents@