php中使用DOM类读取XML文件的实现代码

主要功能：php中使用DOM类读取XML文件
设计知识点：
1、XML节点循环读取
2、用iconv()函数实现编码转换，防止中文乱码
holiday.xml文件如下

<?xml version="1.0" encoding="UTF-8"?> 
<daysOff-overTime> 
<year> 
<yearName>2012</yearName> 
<holiday> 
<holidayName>元旦</holidayName> 
<daysOff> 
<from>2012-1-1</from> 
<to>2012-1-3</to> 
</daysOff> 
<overTime> 
<day>2011-12-31</day> 
</overTime> 
</holiday> 
<holiday> 
<holidayName>春节</holidayName> 
<daysOff> 
<from>2012-1-22</from> 
<to>2012-1-28</to> 
</daysOff> 
<overTime> 
<day>2012-1-21</day> 
<day>2012-1-29</day> 
</overTime> 
</holiday> 
<holiday> 
<holidayName>清明节</holidayName> 
<daysOff> 
<from>2012-4-2</from> 
<to>2012-4-4</to> 
</daysOff> 
<overTime> 
<day>2012-3-31</day> 
<day>2012-4-1</day> 
</overTime> 
</holiday> 
<holiday> 
<holidayName>劳动节</holidayName> 
<daysOff> 
<from>2012-4-29</from> 
<to>2012-5-1</to> 
</daysOff> 
<overTime> 
<day>2012-4-28</day> 
</overTime> 
</holiday> 
<holiday> 
<holidayName>端午节</holidayName> 
<daysOff> 
<from>2012-6-22</from> 
<to>2012-6-24</to> 
</daysOff> 
<overTime/> 
</holiday> 
<holiday> 
<holidayName>中秋节、国庆节</holidayName> 
<daysOff> 
<from>2012-9-30</from> 
<to>2012-10-7</to> 
</daysOff> 
<overTime> 
<day>2012-9-26</day> 
</overTime> 
</holiday> 
</year> 
</daysOff-overTime>

php代码如下：

<?php 
//读取xml文件 
$xmlDoc = new DOMDocument(); 
$xmlDoc->load('http://127.0.0.1/holiday.xml'); 
//获得该xml文件中的所有年份 
$years = $xmlDoc->getElementsByTagName("year"); 
//对每一个年份进行处理 
foreach($years as $year){ 
//获得具体的年份值 
$yearNames = $year->getElementsByTagName("yearName"); 
$yearName = $yearNames->item(0)->nodeValue; 
echo $yearName.'年'.'</br>'; 
//获得该年份下所有的假日 
$holidays = $year->getElementsByTagName("holiday"); 
//对每一个假日进行处理 
foreach($holidays as $holiday){ 
//获得假日名称 
$holidayNames = $holiday->getElementsByTagName("holidayName"); 
$holidayName = $holidayNames->item(0)->nodeValue; 
echo iconv('utf-8','gb2312', $holidayName).': '.'</br>'; 
//获得假日的具体放假日期 
$daysOffs = $holiday->getElementsByTagName("daysOff"); 
$daysOff = $daysOffs->item(0); 
$froms = $daysOff->getElementsByTagName("from"); 
$from = $froms->item(0)->nodeValue; 
$tos = $daysOff->getElementsByTagName("to"); 
$to = $tos->item(0)->nodeValue; 
echo '假期为：'.$from.' 至 '.$to.'</br>'; 
//获得针对该假日的调休日期 
$overTimes = $holiday->getElementsByTagName("overTime"); 
$overTime = $overTimes->item(0); 
$days = $overTime->getElementsByTagName("day"); 
//通过判断，有调休日期则显示，没有则不显示 
if($days->length!=0){ 
echo '调休日为：'; 
foreach($days as $day){ 
echo $day->nodeValue.' '; 
} 
echo '</br>'; 
} 
echo '</br>'; 
} 
} 
?>

输出显示：