Posted in Python onAugust 13, 2013
from sys import argv script, start, end = argv vis = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] ans = [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] def dfs(cur, m): ans[cur] = m if cur == int(end) - int(start) + 1: for i in xrange(int(start), int(end) + 1): print ans[i], return cur = cur + 1 for i in xrange(int(start), int(end) + 1): dfs(cur, i) print dfs(0, start)
pytyon 带有重复的全排列
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