Posted in Python onJuly 08, 2017
本文实例讲述了Python调用微信公众平台接口操作。分享给大家供大家参考,具体如下:
这里使用的是Django,其他类似
# coding=utf-8 from django.http import HttpResponse import hashlib, time, re from xml.etree import ElementTree as ET def weixin(request): token = "your token here" params = request.GET args = [token, params['timestamp'], params['nonce']] args.sort() if hashlib.sha1("".join(args)).hexdigest() == params['signature']: if params.has_key('echostr'): return HttpResponse(params['echostr']) else: reply = """<xml> <ToUserName><![CDATA[%s]]></ToUserName> <FromUserName><![CDATA[%s]]></FromUserName> <CreateTime>%s</CreateTime> <MsgType><![CDATA[text]]></MsgType> <Content><![CDATA[%s]]></Content> <FuncFlag>0</FuncFlag> </xml>""" if request.raw_post_data: xml = ET.fromstring(request.raw_post_data) content = xml.find("Content").text fromUserName = xml.find("ToUserName").text toUserName = xml.find("FromUserName").text postTime = str(int(time.time())) if not content: return HttpResponse(reply % (toUserName, fromUserName, postTime, "输入点命令吧...")) if content == "Hello2BizUser": return HttpResponse(reply % (toUserName, fromUserName, postTime, "查询成绩绩点请到http://chajidian.sinaapp.com/ 本微信更多功能开发中...")) else: return HttpResponse(reply % (toUserName, fromUserName, postTime, "暂不支持任何命令交互哦,功能开发中...")) else: return HttpResponse("Invalid Request") else: return HttpResponse("Invalid Request")
希望本文所述对大家Python程序设计有所帮助。
Python调用微信公众平台接口操作示例
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