javascript onmouseout 解决办法

onmouseout 发现它的触发太敏感，当经过层内文字链时，即触发onmousetout事件，功能不能正常显示，经过一番搜索，整理出来，供大家参考。

1、

<script type="text/javascript"> 
function test(obj, e) { 


if (e.currentTarget) { 

if (e.relatedTarget != obj) { 

 if (obj != e.relatedTarget.parentNode) { 

alert(1); 

} 

} 

} else { 

if (e.toElement != obj) { 

if (obj != e.toElement.parentNode) { 

alert(1); 

} 

} 

} 

} 
</script> 

<div onmouseout="test(this, event)" style="width:100px;height:100px;border:1px #666 solid"> 


<span style="margin:5px;width:100%;height:100%;border:1px #ff0000 solid">faddsf</span>
</div>

2、

var LeaveFunext = function(t,f){for(var p in f){t[p]=f[p]} return t}; 

var IE = '\v' == 'v'; 

var contains = function(wrap,child){ 

if(IE) return wrap.contains(child); 

while(child && typeof(child.parentNode) != "undefind"){ 

if(wrap == child) return true; 

child = child.parentNode; 
} 
return false; 

}; 

var LeaveFun = function(o){ 

var _o = typeof o =="string" ? document.getElementById(o) : o; 

return this == window ? new LeaveFun(_o):LeaveFunext(_o, LeaveFun.prototype); 

}; 

LeaveFun.prototype = { 

mouseleave : function(fn){ 

if(IE){ 

this.attachEvent('onmouseleave',fn); 

}else{ 
this.addEventListener('mouseout',function(e){ 
tar = e.relatedTarget; 
if(!contains(this, tar)){ 
fn.call(this); 
} 

}, false); 

} 

return this; 

} 

}; 

//调用 

LeaveFun('share_customerdiv').mouseleave(function(){document.getElementById('share_customerdiv').style.display ='none';})

3、最简单，但在部分系统上会有轻微闪烁。

<div style="z-index: 11; " onmouseout="this.style.display='none'" onmouseover="this.style.display='block'" > 
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</div>